Question 159567
X=first even positive integer
X+2=second positive integer

The equation is (X)(X+2)=120

Use the distributive property
X^2+2X=120

subtract 120 from both sides

X^2+2X-120=0

This is a quadratic equation

Factor the equation 

Find two numbers that multiplied together =-120
but when addded together gives you +2

I thought of 12 and 10

(X+12)(X-10)=0

Therefore the solution can be either -12 or 10

Since we are dealing with a positive even integer we cannot use -12 therefore the correct answer is 10 and 12
You can double check by plugging in the two integers

(10)(12)=120