<PRE><B>Question 159536</B>
if x+2y+3z=53 and 3x+2y+z=52 what is the value of x+y+z?
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Add &#39;em up:
 x+2y+3z=53
3x+2y+ z=52 
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4x + 4y + 4z = 105
Divide equation 4
x + y + z = {{{105/4}}}
x + y + z = 26{{{1/4}}}
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