Question 159555
How much pure acid should be mixed with 7 gallons of a 40% acid solution in order to get an 80% acid solution?
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acid + acid = acid
0.40*7 + 1.00x = 0.80(7+x)
40*7 + 100x = 80(7+x)
280 + 100x = 560 80x
20x = 280
x = 14 gallons (amount of 100% acid that must be added)
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Cheers,
Stan H.