Question 159497
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Let's appoint the 2 savings accounts as {{{S[A]}}} & {{{S[B]}}}.
{{{S[A]=x}}}, money put down on {{{A}}} account with 2% Annual Interest
{{{S[B]=13500-x}}},money put down on {{{B}}} account with 3% Annual Interest
So,
{{{0.02x+0.03(13500-x)=352.70}}} ---------------------> working eqn
{{{0.02x+405-0.03x=352.70}}}
{{{405-352.70=0.03x-0.02x}}}
{{{52.3=0.01x}}} ----> {{{cross(52.3)5230/cross(0.01)=cross(0.01)x/cross(0.01)}}}
{{{x=5230}}} -----------------------> Amount invested on {{{S[A]}}}
{{{13500-5230=8270}}} --------------> Amount invested on {{{S[B]}}}
In doubt? go back working eqn:
{{{0.02(5230)+0.03(8270)=352.70}}}
{{{104.60+248.10=352.70}}}
{{{352.70=352.70}}}
Thank you,
Jojo</pre>