Question 159327
A) 
(5/6)^3=125/216  probability of no 6 in 3 rolls
1-(5/6)^3=91/216 probability of at least 1 six in 3 rolls.
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B & C
(1/2)^2=1/4 of the time no even number will show up.
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D)
1 - 1/4=3/4 of the time an even number will show up.
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Ed