Question 159295
1) Let one angle be x. The other angle is 2x+6. The two angles together equal 90
so
{{{90 = x + 2x + 6}}}
{{{90 = 3x + 6}}}
{{{84 = 3x}}}
{{{28 = x}}}
The larger angle is 2*28 + 6 = 62.

2)Use the same process as problem one for this one. 
Let x be the angle. The complement is then (90-x). The Supplement is (180-x)
You are told the supplement is 5 times the complement.
So
{{{5*(90-x) = 180-x}}}
{{{450 - 5x = 180 -x}}}
{{{270 = 4x}}}
{{{67.5 = x}}}
The complement is 90-67.5 = 22.5
The supplement is 180 - 67.5 -= 112.5
The