Question 159299
Let the short side be s.
One side is 2s-3
The other side is 2s+7

The perimeter is the sum of the 3 sides and is equal to 114.

So
{{{114 = s + (2s-3) + (2s+7)}}}
{{{114 = 5s + 4 }}}
{{{110 = 5s}}}
{{{22 = s}}}
2*22 - 3 = 44-3 = 41
2*22 + 7 = 44 + 7 = 51

The three sides are 22, 41 and 51

Check your answer. Is there sum 114?