Question 159296
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Let {{{x[1]}}}-----> 1st number
{{{x[2]}}}------------> 2nd number
1st condition, average is 7:
{{{(x[1]+x[2])/2=7}}}
2nd condition: 3 times one number equals half the other,
{{{3x[1]=(1/2)(x[2])}}}
In 2nd condition we get by cross multiplying:
{{{(2)(3)x[1]=x[2]}}}
{{{6x[1]=x[2]}}} ------> condition 3, and substitute in condition 1:
{{{(x[1]+highlight(6x[1]))/2=7}}}
{{{7x[1]=14}}} ----> {{{cross(7)x/cross(7)=cross(14)2/cross(7)}}}
{{{x[1]=2}}} , 1st number
Via condition3:
{{{x[2]=6*2=12}}}, 2nd number
Check via condition 1:
{{{(2+12)/2=7}}}
{{{14/2=7}}}
{{{7=7}}}
Check via condition 2:
{{{3*2=1/2(12)}}}
{{{6=6}}}
Thank you,
Jojo