Question 159290
Let n=first number. So this means that the second number is n+2 and the third is n+4. Since the sum of the three numbers is 0, this means that {{{n+n+2+n+4=0}}}




{{{n+n+2+n+4=0}}} Start with the given equation.



{{{3n+6=0}}} Combine like terms on the left side.



{{{3n=0-6}}} Subtract {{{6}}} from both sides.



{{{3n=-6}}} Combine like terms on the right side.



{{{n=(-6)/(3)}}} Divide both sides by {{{3}}} to isolate {{{n}}}.



{{{n=-2}}} Reduce.



So the first number is -2, the second is {{{-2+2=0}}} and the third is {{{-2+4=2}}}