Question 158449
Solving for {{{w}}} for the below eqn:
Addition ----- {{{system(w^2-2w+1, 2w-5+w^2)}}}
cancel out --- {{{system(w^2-cross(2w)+1,w^2+cross(2w)-5)}}}
continuing ---> {{{2w^2-4=0}}}
{{{2w^2=4}}}
{{{cross(2)w^2/cross(2)=cross(4)2/cross(2)}}}
{{{w=sqrt(2)}}}, ANSWER
want to check it out, go back both eqn:
{{{(sqrt(2))^2-2sqrt(2)+1+(2sqrt(2)-5+sqrt(2)^2)=0}}}
{{{2-2.8284+1+(2.8284-5+2)=0}}}
{{{0.1716+(-0.1716)=0}}}
{{{0=0}}}
Thank you,
Jojo