<PRE><B>Question 159195</B>
1. the sum of two number is 20. what is the least possible sum of their squares?
2. what number exceeds its square by the greatest amount? 
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1. S = x^2 + (20-x)^2
S = x^2 + 400 -40x +x^2
S = 2x^2 - 40x + 400
Set 1st derivative = 0
4x - 40 = 0
x = 10
10^2 + 10^2 = 200
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2. D = x-x^2
Set 1st derivative = 0
1-2x = 0
x = 1/2




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