Question 159169
i got the same answer as you although i kept the denominator as 1 number.
original equation is {{{(5-3*i)/(-3-2*i)}}}
i multiplied top and bottom by {{{(-3+2i)}}} to remove imaginary number from the denominator.
result was {{{(-9+19*i)/13}}}
which is the same answer you got.
looks good from what i can tell.
{{{i^2=(-1)}}} is correct.