Question 159163
{{{ (5-3i)/(-3-2i) }}}
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To get rid of the 'i' from the numerator, multiply by (-3+2i)/(-3+2i):
{{{ (5-3i)/(-3-2i) * (-3+2i)/(-3+2i) }}}
{{{ ((5-3i)(-3+2i))/(9-4) }}}
{{{ ((5-3i)(-3+2i))/(5) }}}
{{{ (-15+10i+9i+6)/(5) }}}
{{{ (-9+19i)/(5) }}}
{{{ -9/5 + (19/5)i }}}