Question 159121
x^2/3-x-1/6 -b+-sqr rt of b^2-4ac/ 2a
a=? b=-1 c=-1/6
I am stuck as to what "a" is.
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If it's {{{x^2/3 - x - 1/6}}}, then a = 1/3
To solve it, multiply by 6
2x^2 - 6x - 1 = 0
*[invoke solve_quadratic_equation 2,-6,-1]
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The onsite solver doesn't handle the coefficients well, but you can figure it out from what's shown.