Question 21824
{{{3+y/4=-y/8}}}


Multiply both sides by the LCD of the problem which is 8.  This clears the fractions:
{{{ 8*3 + 8*(y/4) = 8*(-y/8) }}}
{{{24 + 2y = -y }}}


Subtract 2y from each side:
{{{24+2y-2y = -y -2y }}}
{{{24 = -3y}}}


Divide both sides by -3:
{{{24/-3 = (-3y)/-3}}}
{{{-8=y}}}


You might want to check this:

{{{3 + (-8)/4 = 8/8}}}
{{{3-2 = 1}}}
It checks.


R^2 at SCC