Question 159076
{{{(16x^2 + 8x - 4) / 4}}}
Each term get divided by {{{4}}}
This is no more difficult than:
{{{ (16 + 8 - 4)/4}}}
If I do the addition,
{{{20/4 = 5}}}
Now, dividing each term by {{{4}}},
{{{16/4 + 8/4 - 4/4 = 4 + 2 - 1}}}
{{{4 + 2 - 1 = 5}}}
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The solution to your problem is
{{{(16x^2 + 8x - 4) / 4 = 16x^2/4 + 8x/4 - 4/4}}}
{{{16x^2/4 + 8x/4 - 4/4 = 4x^2 + 2x - 1}}} answer