Question 22180
{{{(-3x^2y^3)= -27x^6y^3 }}} (my answer)


In the first case, notice that the parentheses are outside the exponent.  This means that the 3 exponent just inside the parentheses applies ONLY to the y.  You do NOT cube anything else.  Your answer is not correct.


If the problem had been written:
{{{(-3x^2y)^3 }}} with the parentheses on the INSIDE of the exponent, then you would be correct to say: 
{{{-27x^6y^3}}}.


The expression {{{ (-3x^2y^3) }}} cannot be simplified.


{{{2(x^(-3)*y^2)^2 }}}  I'm not sure what you tried to do in the second one.  This is correct, if I've interpreted your problem correctly.

{{{ 2(x^(-6)*y^4 )}}}
{{{2(1/(x^6))*y^4) }}}
{{{ (2y^4)/(x^6) }}}


R^2 at SCC