Question 158775
{{{A}}} is a compliment of {{{B}}}.
therefore {{{A+B=90}}} ----> working eqn, but {{{A=(1/3)B}}}, substitute in working eqn:
{{{(1/3)B+B=90}}}
{{{(B+3B)/3=90}}}
{{{4B=3*90=270}}}
{{{cross(4)B/cross(4)=cross(270)67.50/cross(4)}}}
{{{B=67.50deg}}}
{{{A+67.50=90}}}
{{{A=90-67.5=22.5deg}}}
: {{{22.5+67.50=90}}}
{{{90=90}}}, complement
Thank you,
Jojo