Question 158861
{{{2^5 = (1+0.23x)^3}}} -------------> basic eqn
{{{32=(1+0.23x)^3}}}, raise the whole eqn by {{{1/3}}}
{{{32^(1/3)=(1+0.23x)^3^(1/3)}}}, cancel out the exponent on variable w/ "x"
{{{3.1748=1+0.23x}}}
{{{3.1748-1=0.23x}}}
{{{2.1748=0.23x}}}
{{{cross(2.1748)9.45565/cross(0.23)=cross(0.23)x/cross(0.23)}}}
{{{x=9.45565}}}
check it out, go back basic eqn:
{{{2^5=(1+0.23(9.45565))^3}}}
{{{32=(1+2.1748)^3}}}
{{{32=3.1748^3}}}
{{{32>=31.99999999}}}
.{{{32=32}}}
Thank you,
Jojo