Question 158713
Any odd number can be written as 2n+1 for some integer, n.  So, the sum of 3 consecutive odd integers is 2n+1 + 2n+3 + 2n+5.

Then, we are told that 2(2n+1) + 6 = 2n+3 + 2n+5

So, 4n + 2 + 6 = 4n + 8

Or, 4n + 8 = 4n + 8

Any value of n obviously satisfies this equation so we have a triviality (ie. n can equal anything).

Therefore, there is not one answer.

2n+1 + 2n+3 + 2n+5 = 6n + 9 so we could say in set notation the answer lies in the set {6n + 9 | n is an integer}