Question 158540
3x over 2y * y^2 over 6 = ?
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(3x/2y)* (y^2/6)
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Cancel any factors that are common to a numerator and a denominator,
such as y, and 3, to get:
=(x/2)* (y/2)
Now multiply the numerators and multiply the denominators to get:
=(xy)/4
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Cheers,
Stan H.