Question 158520
Write a linear equation through the point (-1,-5) perpendicular to the line 
y = -3x + 4

We are looking for another equation.

The quation we are looking for must have a slope that is the negative reciprocal of your given equation.

We are given a point and from the given equation we know the slope is -3.

We use the point-slope formula to find our equation.

(y - y1) = m (x - x1), where m = slope.

y - (-5) = -3(x - (-1))

y + 5 = -3(x + 1)

y + 5 = -3x -3

y = -3x - 3 - 5

y = -3x - 8

The only thing we need to do now is change -3 into 1/3.

The equation that is perpendicular to your given equation is

y = (1/3)(x) - 8