Question 158470
X, X+2, X+4, X+6 ARE THE 4 EVEN INTEGERS.
2(X+6)+(X+2)/2=68
2X+12+(X+2)/2=68
2X+(X+2)/2=68-12
(2*2X+X+2)/2=56
(4X+X+2)/2=56
5X+2=2*56
5X=112-2
5X=110
X=110/5
X=22 THE FIRST INTEGER.
PROOF:
2(22+6)+(22+2)/2=68
2*28+24/2=68
56+12=68
68=68