Question 21854
WE WANT 1+3+5+7+.......112 NUMBERS
THE GENERAL FORMULA FOR Tn=Nth.TERM=A+(N-1)D...WHERE A IS THE FIRST TERM =1 IN THIS CASE...N=NUMBER OF TERMS =112 IN THIS CASE....D=CONSTANT DIFFERENCE BETWEEN 2 CONSECUTIVE NUMBERS =2 HERE.
THE FORMULA FOR Sn=SUM UP TO N TERMS =(N/2){2A+(N-1)D}..WITH SAME TERMINOLOGY.HENCE 
S112=(112/2){2*1+(112-1)*2}=56*(2+111*2)=56*(224)=12544