Question 158355
{{{x2 – 3x – 3 = -5}}}
becomes: {{{x^2-3x-3+5=0}}}
{{{x^2-3x+2=0}}}, Take {{{a=1}}}, {{{b=-3}}}, & {{{c=2}}}
Use: {{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}
ANSWER: {{{(x-2)(x-1)=0}}}
Since it's a perfect square it's factorable that's why.
thank you,
Jojo