Question 158290


{{{x+3y=6}}} Start with the given equation.



{{{3y=6-x}}} Subtract {{{x}}} from both sides.



{{{3y=-x+6}}} Rearrange the terms.



{{{y=(-x+6)/(3)}}} Divide both sides by {{{3}}} to isolate y.



{{{y=((-1)/(3))x+(6)/(3)}}} Break up the fraction.



{{{y=-(1/3)x+2}}} Reduce.



So the equation {{{y=-(1/3)x+2}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=-1/3}}} and the y-intercept is {{{b=2}}} note: the y-intercept is the point *[Tex \LARGE \left(0,2\right)]