Question 158279
{{{-3x<-12 }}} Start with the given inequality



{{{cross((-1/3)(-3))x>-12(-1/3) }}} Multiply both sides by {{{-1/3}}} (which is the multiplicative inverse of -3) to isolate "x". 


Note: multiplying both sides by a negative number will change the sign from a "less than" sign to a "greater than" sign.



{{{x>(-12)/(-3) }}} Multiply



{{{x>4 }}} Reduce




So the solution set is  *[Tex \LARGE \left\{x\|x>4\right\}]



Also the answer in interval notation is *[Tex \LARGE \left(4,\infty\right)]



Here's the graph of the solution set


{{{drawing(500,80,-6, 14,-10, 10,
number_line( 500, -6, 14),

arrow(4,0,14,0),
arrow(4,0.30,14,0.30),
arrow(4,0.15,14,0.15),
arrow(4,-0.15,14,-0.15),
arrow(4,-0.30,14,-0.30),

circle(4,0,0.3),
circle(4,0,0.3),
circle(4,0,0.3),
circle(4,0,0.3-0.02)
)}}} Note: the endpoint is an open circle