Question 22590
And you want to graph it?  You can either solve for y, and use the slope-intercept method, or you can find the two intercepts, graph the two points, and connect the points.


By the slope-intercept method:
{{{2x + 3y = 8}}}

{{{ 3y = -2x +8}}}

{{{ (3y)/3 = (-2/3)x +8/3 }}}


From this the y-intercept is 8/3 (almost 3) and the slope is {{{-2/3}}} (rise of -2 and run of 3, which means starting from the y-intercept, go DOWN 2 and RIGHT 3, and put the next point.


By the x and y-intercept method:
Let x= 0:  3y = 8, so {{{y=8/3}}}

Let y=0:  2x=8, so {{{x=4}}}.

Graph the points.  


Either way, it should look like this:

{{{ graph(300,300, -6,6,-6,6, (-2/3)x+8/3)}}}


R^2 at SCC