Question 23158
Normally you would need to use the distance formula to find the three distances between these points.  However, comparing P(-2,6) and Q(-2,0), you can see that P is directly above Q, at a distance of 6 units.  Comparing Q(-2,0) and R(5,0), you can see that these are both on the x axis at a distance of 7 units.  Moreover, you can see that line PQ is perpendicular to line QR and the x-axis, so this is a right triangle.  You can use the Theorem of Pythagoras to find PR = {{{sqrt((6^2 +7^2)) = sqrt((36+49))=sqrt(85) }}}.


R^2 at SCC