Question 23157
I'm not sure what you mean by this.  It looks like you have this:
{{{ ((2*x^7*y^2)^3)/((4*x*y^3)^3) }}}.


Maybe if this is NOT what you meant, you can use this illustration to re-state your problem and resubmit it.

{{{ ((2*x^7*y^2)^3)/((4*x*y^3)^3) }}}
{{{ (2^3x^21*y^6)/(4^3x^3y^9) }}}

{{{ (8x^21*y^6)/(64x^3y^9) }}}


It might be a good idea to split this rather LARGE problem into three smaller problems:

{{{(8/64)*((x^21)/(x^3))*((y^6)/(y^9))}}}


Each of these smaller fractions reduces:
{{{(1/8)* (x^(21-3))*(y^(6-9))}}}
{{{(1/8)* (x^(18))*(y^(-3))}}}


Remember that a negative exponent, does NOT mean that the answer is negative!  Rather, it means that you have a fraction with numerator of 1, and a positive denominator.  In this instance, {{{y^(-3) = 1/(y^3) }}}.


So, {{{(1/8)* (x^(18))*(y^(-3))}}}
{{{(1/8)* (x^(18))*(1/(y^3)) }}}


{{{ (x^18)/(8y^3) }}}


R^2 at SCC