Question 158082
{{{(3x+1)^6(2x-5)^0.5+(2x-5)^1.5(3x+1)^5}}}
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Substitute {{{A}}} for {{{(3x+1)}}}
Substitute {{{B}}} for {{{(2x-5)}}}

Then

{{{(3x+1)^6(2x-5)^0.5+(2x-5)^1.5(3x+1)^5}}}

becomes:

{{{A^6*B^0.5+B^1.5*A^5}}} 

Factor out the smaller power of {{{A}}} which is {{{A^5}}}
Factor out the smaller power of {{{B}}} which is {{{B^0.5}}}

{{{A^5*B^0.5(A^1+B^1)}}}

{{{A^5*B^0.5(A+B)}}}

Replace {{{A}}} by {{{(3x+1)}}}
Replace {{{B}}} by {{{(2x-5)}}}

{{{(3x+1)^5(2x-5)^0.5((3x+1)+(2x-5))}}}

{{{ (3x+1)^5(2x-5)^0.5(3x+1+2x-5) }}}

{{{ (3x+1)^5(2x-5)^0.5(5x-4) }}}

Edwin</pre>