Question 158021
a^2+5ab^2-3b^2+7a^2b-ab^2=a^2

Take out an (a)

a(a+5b^2-3b^2+7ab-b^2)=a(a)

Cancel out the (a's)

a+5b^2-3b^2+7ab-b^2=a

Subtract 5b^2 3b^2 and b^2

a+b^2+7ab=a

Subtract a on both sides

b^2+7ab=0

Transfer 7ab on the other side of the equal sign

b^2=-7ab

Take out a b from both sides

b(b)=(-7a)b

Cancel out the b's

b=-7a is your final answer

Hope that helps!!!

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