Question 157916
{{{ d(x)=(x+2)^3+3}}} Start with the given function



{{{4*d(x)=4((x+2)^3 +3)}}} Multiply both sides by 4 (since we're looking for the function that is "4 times larger")



{{{4*d(x)=4(x+2)^3 +4(3)}}} Distribute



{{{4*d(x)=4(x+2)^3 +12}}} Multiply



So the new function for d(x) that is 4 times larger is  a) {{{d(x)=4(x+2)^3 +12}}}