Question 157951
{{{y= -3-3x}}} Start with the given equation



{{{y= -3x-3}}} Rearrange the terms.





<h4>x-intercept</h4>

To find the x-intercept, plug in {{{y=0}}} and solve for x



{{{y=-3x-3}}} Start with the given equation.



{{{0=-3x-3}}} Plug in {{{y=0}}}.



{{{3=-3x}}} Add 3 to both sides.



{{{-1=x}}} Divide both sides by -3 to isolate x



So the solution is {{{x=-1}}}



So the x-intercept is *[Tex \LARGE \left(-1,0\right)].



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<h4>y-intercept</h4>

To find the y-intercept, plug in {{{x=0}}} and solve for y



{{{y=-3x-3}}} Start with the given equation.



{{{y=-3(0)-3}}} Plug in {{{x=0}}}.



{{{y=-0-3}}} Multiply {{{-3}}} and 0 to get 0.



{{{y=-3}}} Combine like terms.



So the y-intercept is *[Tex \LARGE \left(0,-3\right)].




So we have these intercepts:

x-intercept: *[Tex \Large \left(-1,0\right)]


y-intercept: *[Tex \Large \left(0,-3\right)]




Now plot the two points *[Tex \Large \left(-1,0\right)] and *[Tex \Large \left(0,-3\right)] 


{{{drawing(500, 500, -5, 5, -5, 5,
graph(500, 500, -5, 5, -5, 5,0),
circle(-1,0,0.0444444444444444),
circle(-1,0,0.0744444444444445),

circle(0,-3,0.0444444444444444),
circle(0,-3,0.0744444444444445)


)}}}



Now draw a line through the two points to graph {{{y=-3x-3}}}

{{{drawing(500, 500, -5, 5, -5, 5,
graph(500, 500, -5, 5, -5, 5,(-3-3*x)/1),
circle(-1,0,0.0444444444444444),
circle(-1,0,0.0744444444444445),

circle(0,-3,0.0444444444444444),
circle(0,-3,0.0744444444444445)


)}}} graph of {{{-3x-3}}} through the x-intercept *[Tex \Large \left(-1,0\right)] and the y-intercept *[Tex \Large \left(0,-3\right)]