Question 157970
ONE TOO MANY = SIGNS. 
CORRECT & RESUBMIT.
UNLESS THE SECOND = SIGN (2Z=3) SHOULD BE A + SIGN THEN:
7=12Z+18-5
12Z=7-18+5
12Z=-6
Z=-6/12
Z=-1/5 OR -.5
PROOF:
7=12*-.5+18-5
7=-6+18-5
7=18-11
7=7