Question 157900
{{{x=-2}}}, {{{x=2}}}, or {{{x=3}}} Start with the given zeros



{{{x+2=0}}}, {{{x-2=0}}}, or {{{x-3=0}}} Get all values to the left side



{{{(x+2)(x-2)(x-3)=0}}} Use the zero product property to combine the three equations



{{{(x^2-4)(x-3)=0}}} FOIL the first two parenthesis



{{{x^3-3x^2-4x+12=0}}} FOIL



So the polynomial of degree 3 {{{y=x^3-3x^2-4x+12}}} has the zeros -2, 2, 3