Question 157861
{{{3(x-2)^2-3(x-2)-6=0}}}
Let u=x-2
{{{3u^2-3u-6=0}}}
{{{(3u+3)(u-2)=0}}}
Now substitute back for u.
{{{(3u+3)(u-2)=0}}}
{{{(3(x-2)+3)((x-2)-2)=0}}}
{{{(3x-6+3)(x-4)=0}}}
{{{(3x-3)(x-4)=0}}}
{{{3(x-1)(x-4)=0}}}