Question 157835
Write an equation of the line that is parallel to y= 3x-4 and passes through point (0,-3). 
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Lines that are parallel have the same slope.  The eqn is in slope-intercept form, y = mx+b, so the slope, m, is 3.
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Then, use the given point in the slope-intercept form:
y-y1 = m*(x-x1) where (x1,y1) is the given point (0,-3)
y -(-3) = 3*(x - 0)
y+3 = 3x
y = 3x - 3  slope-intercept form
3x-y = 3  standard form