Question 157804
Hi, Hope I can help
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the problem is how many {{{ 2/3 }}}'s are in 1. I don't know how to work this out. thanks
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This is pretty easy, all you do is divide {{{ 2/3 }}} from {{{ 1 }}}
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Here is the solution
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{{{ 1/(2/3) }}} = {{{ (1/1)/(2/3) }}} = {{{ (1/1)(3/2) }}} = {{{ (3/2) }}}
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There are {{{ 3/2 }}} {{{ 2/3}}}'s in 1
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{{{ 3/2 }}} is your answer
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Lets do some other problems
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How many 4's are in 8, {{{ 8/4 }}} = {{{ 2 }}}, there are two 4's in 8
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How many 9's are in 63, {{{ 63/9 }}} = {{{ 7 }}}, there are seven 9's in 63
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How many 10's are in 5, {{{ 5/10 }}} = {{{ 1/2 }}}, there is {{{ 1/2 }}} of 10 in 5
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How many 12's are in (-2), {{{ -2/12 }}} = {{{ -1/6 }}}, there is {{{ -1/6 }}} of 12 in (-2)
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How many 7's are in {{{ 4/5 }}}, {{{ (4/5)/7 }}} = {{{ (4/5)(1/7) }}} = {{{ 4/35 }}}, there is {{{ 4/35 }}} of 7 in {{{ 4/5 }}}
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In our problem
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How many {{{ 2/3 }}}'s are in 1, {{{ 1/(2/3) }}} = {{{ (1/1)(3/2) }}} = {{{ (3/2) }}}
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Our answer = {{{ 3/2 }}} or {{{ 1.5 }}},(that's how many {{{2/3}}}'s there are in 1)
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Hope I helped, Levi