Question 23146
 (x-2)(2x+1)(2x-3)>0
find the range of x ?
 
 There are three roots of (x-2)(2x+1)(2x-3) = 0,namely 2, 3/2 and -1/2 
 (in descending order).

 Hence,  (x-2)(2x+1)(2x-3)>0 --> x >2 or  -1/2 < x < 3/2.

 That is, the solution set of (x-2)(2x+1)(2x-3)>0 is
 (-1/2, 3/2) U (2, +oo) .

 Draw a diagram on the real line you will see. 

 Kenny