Question 157772
Let ¨x= 1st integer
x+1 = 2nd integer
x+2 = 3rd integer
x+3 = 4th integer
Then, (x+1+x+2+x+3)-2x=16 ----------------------- condition, twice the 1st is subtracted from the sum of 2nd, 3rd & 4th:
continuing;
3x-2x=16-6
x=10 ------------------------------------- 1st integer
10+1=11 ---------------------------------- 2nd integer
10+2=12 ---------------------------------- 3rd integer
10+3=13 ---------------------------------- 4th integer
To check, go back to the condition:
11+12+13-2(10)=16
36-20=16
16=16
Thank you,
Jojo