Question 157700
Let's see the {{{Area[cyl]=2(pi)r^2+2(pi)(r)(h)}}}
{{{r=10ft}}}, {{{h=24ft}}}
{{{A[cyl]=2(pi)10^2+2(pi)(10)(24)}}}
{{{A[cyl]=200(pi)+480(pi)}}}
{{{A[cyl]=680(pi)ft^2}}}, TOTAL SURFACE AREA to be painted
No. of gallon in 1 coat:
{{{(680(pi)cross(ft^2))(1gal/300cross(ft^2))}}}
{{{7.121gal}}} ------> 1 coat
Since 3 coats: {{{7.121gal*3=21.36gal}}} -----> for 3 coats
: USE {{{22 GAL}}} PAINT
Thank you,
Jojo