Question 22523
	I1	=	0.02Sin(wt)																						
	I2	=	0.032Cos(wt-pi/3)					=	0.032{Cos(wt)Sin(pi/3)+Sin(wt)Cos(pi/3)}													=			
	I2	=	0.032{0.866Cos(wt)+0.5Sin(wt)}									=	0.028Cos(wt)+0.016Sin(wt)												

	I1+I2		=	0.02Sin(wt)+0.028Cos(wt)+0.016Sin(wt)																					
			=	0.036Sin(wt)+0.028Cos(wt)																					
			NOW MULTIPLY AND DIVIDE WITH SQUARE ROOT OF (0.036^2+0.028^2)=																						0.0456
			LET Sin(a)=0.028/0.0456…SO THAT…Cos(a)=0.036/0.0456…HENCE WE GET 																						
	I1+I2		=	Sin(wt)Cos(a)+Cos(a)Sin(wt)									=	Sin(wt+a)…..WITH A BEING ARC SIN (0.028/0.0456)											
														OR …Sin(a)  =   (0.028/0.0456)