Question 157655
No.
Although your final answer is correct your work shows that you don't understand how to get there.
f(x)=y=-x^2-5x+3 I assume that this is the problem. You didn't put a number for the power in the equation you submitted.
If the coefficient of x^2 is negative then it is a maximum and vise versa.
The formula for the maxima or minima at x is x=-b/2a
x=-(-5)/(2*-1)
=5/-2
=-5/2=-2.5
y=-2.5^2-(5*-2.5)+3
=-6.25+12.5+3
=9.25
.
Ed