Question 157516
{{{2*log(10,(x)) + (1/2)log(10,(x)) - 3*log(10,(x))=log(10,(x^2)) + log(10,(x^(1/2))) - log(10,(x^3))=log(10,(x^2*x^(1/2))) - log(10,(x^3))=log(10,(x^(2+1/2))) - log(10,(x^3))=log(10,(x^(5/2))) - log(10,(x^3))=log(10,((x^(5/2))/(x^3)))=log(10,(x^(5/2-3)))=log(10,(x^(-1/2)))}}}



So {{{2*log(10,(x)) + (1/2)log(10,(x)) - 3*log(10,(x))=log(10,(x^(-1/2)))}}} where {{{x>0}}}