Question 157418
Solve for x:
{{{(x^2-9)/(x+1) <= 0}}} You're correct in factoring the numerator.
{{{(x-3)(x+3)/(x+1) <= 0}}} Now multiply both sides by (x+1)
{{{(x-3)(x+3) <= 0}}} because {{{0*(x+1) = 0}}}
Finally:
{{{x-3 <= 0}}} or {{{x+3 <= 0}}} so...
{{{x <= 3}}} or {{{x <= -3}}}