Question 157392
solving for {{{24/(x-2)+24/(x+2)=5}}}
first multiply both sides of the equation by (x-2)*(x+2) to remove the denominators.
equation becomes {{{24*(x+2) + 24*(x-2) = 5*(x-2)*(x+2)}}}
multiplying out on both sides of the equation and it becomes
{{{(48*x) = 5*(x^2-4)}}} which then becomes
{{{48*x = 5*x^2 - 20}}}
moving all terms to one side of the equation we get the quadratic equation of
{{{5*x^2 - 48*x - 20 = 0}}}
this factors out to
{{{(5*x+2)*(x-10)=0}}}
and that's your answer.