Question 157379
my interpretation of twice the weight of the other exams is that the final exam would be the same as having taken 2 exams.
that means joe will have taken 5 exams rather than 4.
5 exams times 89 means the total score would have to be greater than 445.
the 3 exams total 79 + 96 + 84 = 259.
the equation then becomes 259 + 2x > 445.
this becomes 2x > 186.
this becomes x > 93.
joe has to get a score > 93 on the final exam to get an overall score > 89 to get an A in the course.
averaging the 5 test scores of 79, 96, 84, 93, 93, we get a total of 445 / 5 = 89.
this confirms the mathematics is correct based on the assumption.
he has to get > 93 on the final exam.