Question 157029
{{{y=x+8}}} ---------------> 1
{{{y=-x+4}}} -----------------> 2
Since 1 = 2, equate both:
{{{x+8=-x+4}}}
{{{x+x=4-8}}}
{{{2x=-4}}} ---> {{{cross(2)x/cross(2)=cross(-4)2/cross(2)}}}
{{{x=-2}}}
Substitute in 1 & 2:
{{{y=-2+8=6}}}
{{{y=-(-2)+4=2+4=6}}}
: 1 =2
Thank you,
Jojo