Question 156989
this is what i think the answer should be.
in general, {{{(x^(-a)) = 1/(x^a)}}} and {{{a / (b/c) = (a*c)/b}}}
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{{{((x*y^5)/((x^-4)*(y^2)))^-2}}}
=
{{{1/((x*y^5/((1/x^4)*(y^2)))^2)}}}
=
{{{1/((x*y^5*x^4)/y^2)^2}}}
=
{{{1/(x^5*y^3)^2}}}
=
{{{1/(x^10*y^6)}}}